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DriveWorks Solo 21
DWLambda

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DWLambda

DWLambda allows custom, reusable functions to be created.

DWLambda effectively adds your own functions to a DriveWorks Project and can be used to:

  • create commonly used formula
  • eliminate the need to recreate the same formula in many places
  • create complex formula
  • embed existing functions within the formula

DWLambda is added to a Project by:

  1. Creating the DWLambda, typically as a Variable.
  2. Consuming the Variable as a new, custom function.

    The new function passes values into the parameters declared in the DWLambda.

Syntax

DWLambda([Collection of Parameters], [Function])

Where:

Parameters are the names of Lambda References to be used within the Lambda Function. Each parameter is separated with a comma (,), for example a,b,c.

Function is the Lambda function to be executed. The function references each named parameter, for example a*b/c.

Examples

Convert inches to millimeters

Create the Variable ConvertInchToMM and apply the following DWLambda function:

DWLambda(inch, 
         inch * 25.4
         )

Next use the Variable anywhere the conversion is required, as follows:

DWVariableConvertInchToMM(5)

will return 127 (5*25.4).

Or

DWVariableConvertInchToMM(TextBox1Return)

will return 50.8 if the TextBox1 control equals 2 (2*25.4).

Volume (of a cube)

Create the Variable Volume and apply the following DWLambda function:

DWLambda(height, width, depth,
         height * width * depth
         )

Next use the Variable anywhere the conversion is required, as follows:

DWVariableVolume(3, 5, 2)

will return 30 (3*5*2).

Or

DWVariableVolume(HeightReturn, WidthReturn, LengthReturn)

will return 30 when the controls equal 3, 5 and 2 (3*5*2).

Hole Pitch

Create the Variable HolePitch and apply the following DWLambda function:

DWLambda(Length, FirstHole, LastHole, HoleQty,
        (Length-FirstHole-LastHole)/(HoleQty-1)
        )

Next use the Variable anywhere the HolePitch is required, as follows:

DWVariableHolePitch(LengthReturn, 50, 75, 11)

will return 287.5 when the control equals 3000 ((3000-50-75) / (11-1)).

Volume (of a cylinder)

This example demonstrates using a variable that calculates the height (DWVariableCylinderHeight) and the DriveWorks Functions Pi and Power within a DWLambda.

Create the Variable VolumeCyl and apply the following DWLambda function:

DWLambda(radius,
         PI() * Power(radius,2) * DWVariableCylinderHeight
         )

Next use the Variable anywhere the conversion is required, as follows:

DWVariableVolumeCyl(20)

will return 376991.1 = Pi * 20 2 * 300 (the result of DWVariableCylinderHeight).